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Stats Assignment

Autor:   •  November 23, 2015  •  Coursework  •  340 Words (2 Pages)  •  736 Views

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Stats Assignment 3

Brandon Humber

November 10, 2015


  1. a) Car Price mean = 14.1, Age of Car mean = 11.5

Car Price Squared Standard Deviation

Age of Car Squared Standard Deviation

6 - 14.1 = -8.1 = 65.61

20 - 11.5 = 8.5 = 72.25

9 - 14.1 = -5.1 = 26.01

18 - 11.5 = 6.5 = 42.25

12 - 14.1 = -2.1 = 4.41

10 - 11.5 = 1.5 = 2.25

15 - 14.1 = 0.9 = 0.81

8 - 11.5 = -3.5 = 12.25

18 - 14.1 = 3.9 = 15.21

9 - 11.5 = -2.5 = 6.25

25 - 14.1 = 10.9 = 118.81

4 - 11.5 = -7.5 = 56.25

Total

230.86

191.53

Standard Deviation

15.19

13.84

b) Correlation = 119.62 x 3

                  6-1 x 15.19 x 13.84

=358.86  = 0.34

1051.15

c) b1 = 0.34 x 15.19/13.84 = 0.37

b0 = 11.5 + 0.34 (14.1) = 16.29

d) y = 16.29 + 0.34 x 25 = 24.79

2. a) 70%

b) Joint probability - adults under 50 and bank online.

c)

Bank Online

Don’t Bank Online

Totals

Under 50

25%

15%

40%

Over 50

5%

55%

60%

Totals

30%

70%

100%

d) 25%

3. a) Midterm 1 Sum:  16805.45

Midterm 2 Sum: 15248.18

Midterm 3 Sum: 15832.8

Final Exam Sum: 15754

b)

[pic 1]

c) Correlation Coefficients:

Midterm 1: 0.599533

Midterm 2: 0.588109

Midterm 3: 0.720151

Line Equations:

Midterm 1: y = 30.58087 + 0.59533 (Midterm 1 Mark), where the slope is 0.59533 multiplied by the mark on Midterm 1, and the intercept is 30.58087.

...

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