Egm 510 - Decision Making
Autor: Eman_A • August 23, 2015 • Study Guide • 604 Words (3 Pages) • 687 Views
[pic 1]
Engineering and Technology Management
EGM 510
Assignment 2
Decision Making
Eman Alshuweihi
201410538
Question (1):
- Alphabet Blocks (B): 1 hour of wood working and 2 hours of painting.
- Wooden Trucks (T): 3 hours of wood working and one hour of painting.
The problem:
How many boxes of blocks (B) and trucks (T) should you make each week to maximize profit?
Decision variable:
- Let (B) = number of boxes of Alphabet blocks per week
- Let (T) = number of boxes of Wooden trucks per week
Objective Function:
profit is $30 per box of blocks and $40 per box of trucks.
Maximize P= 30B + 40T
Constraints:
(each working 40 hours per week) employ three wood workers and two painters
1B + 3T ≤ 120 1 hour of wood working and 2 hours of painting.
2B + 1T ≤ 80 3 hours of wood working and one hour of painting.
solve two Equations:[pic 2]
2B + 1T ≤ 80
Mult. by (-2) 1B + 3T ≤ 120 -2B - 6T ≤ -240[pic 3][pic 4][pic 5]
-5 T ≤ -160 T =32[pic 6]
2B + 1T ≤ 80 2B + 1(32) ≤ 80 B=24[pic 7][pic 8]
The profit that can the company get by those numbers of boxes:
P= 30B + 40T
P= 30(24) + 40(32) = $2000 So, the company can reach the maximum profit that equals $2000 by making 24 boxes of blocks and 32 boxes of trucks weekly.
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