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Develop a Network Drawing for Hill Construction and Determine the Critical Path. How Long Is the Project Expected to Take?

Autor:   •  April 18, 2016  •  Exam  •  709 Words (3 Pages)  •  1,584 Views

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1. Develop a network drawing for Hill construction and determine the critical path. How long is the project expected to take?

Answer:

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Critical Path[pic 4]

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Critical Path[pic 6]

Critical Path:

A-C-D-G-H-I-L           = 30+65+55+30+20+30+30= 260 DAYS

2. What is the probability of finishing in 270 days? What is the probability of finishing in more than 280 days?

Answer:

Project Variance

319.4444444

Project Standard Deviation

√Variance

√319.4444444

17.87 Days

Probability to finish in 270 days

Z=(Due Date -Expected Date)/Project standard Deviation

(270-260)/17.87

Z

0.56

Checking the z=0.56 on the  table we can observe that the probability (T<=270) is 71%

Probability to finish in more than 280 days

Z=(Due Date -Expected Date)/Project standard Deviation

(280-260)/17.87

Z

1.12

 

 

Checking the z=1.12 on the  table we can observe that the probability (T>280) is (1-0.8686) i.e 13.14%

3. If it is necessary to crash to 240 days, how would Hill do so, and at what costs? As noted in the case, assume that optimistic time estimates can be used as crash time. 

Answer:

Critical Path

Crash Costs Per Day on Critical Path

Crash Times (Optimistic) on Critical Path

 

($)

 

A

1500

20

C

4000

50

D

1900

30

G

2500

25

H

2000

10

I

2000

20

L

4500

20

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Critical Path[pic 8]

Crashing down 20 days will be effective if Hill crashes 10 days in A. Hill cannot crash down more as crash time cannot go below the optimistic value.

Crash down of A by 10days = 10 * 1500 =$15000

For crashing 10 more, we need to crash in the next least Costs Per Day activity i.e D. We will crash 10 days from D.

Crash down of D by 10days = 10 * 1900 =$19000

...

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